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A chemist prepares a solution of aluminum sulfite by measuring out 109 umol of aluminum sulfite into a 350 mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mmol/L of the chemist's aluminum sulfite solution. Be sure your answer has the correct number of significant digits.

Answer :

SvetkaChem

Answer:

0.311 mmol/L

Explanation:

109  μmol = 109*10^(-6) mol

109*10^(-6) mol = 109*10^(-6) mol*(10^3 mmol/1mol) = 109*10^(-3) mmol =

=0.109 mmol

350 mL = 0.350 L

0.109 mmol/0.350 L = 0.311 mmol/L

samueladesida43

The concentration in mmol/L of the chemist's aluminum sulfite solution prepared by measuring out 109 umol of aluminum sulfite into a 350 mL volumetric flask is 0.31mmol/L.

How to calculate concentration?

The concentration of a solution can be calculated by dividing the number of moles of the substance by its volume.

According to this question, a chemist prepares a solution of aluminum sulfite by measuring out 109 umol of aluminum sulfite into a 350 mL volumetric flask and filling the flask to the mark with water.

  • Volume in L = 350/1000 = 0.35L
  • no of moles in mmol = 0.109mmol

Concentration = 0.109 ÷ 0.35

Concentration = 0.31mmol/L

Therefore, the concentration in mmol/L of the chemist's aluminum sulfite solution prepared by measuring out 109 umol of aluminum sulfite into a 350 mL volumetric flask is 0.31mmol/L.

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