Answer:
539.76 moles of O₂
Explanation:
Equation of reaction:
4Al + 3O₂ → 2Al₂O₃
From the equation of reaction above, 4 moles of Al will react with 3 moles of O₂
We can use mole-concept to find the number of moles of O₂.
4 moles of Al = 3moles of O₂
719.68 moles of Al = x moles of O₂
X = (3 × 719.68) / 4
X = 2159.04 / 4
X = 539.76 moles
539.76 moles of O₂ will react with 719.68 moles of Al
Answer:
[tex]n_{O_2}=959.57molO_2[/tex]
Explanation:
Hello,
In this case, given the reaction:
[tex]4Al (s) + 3O_2(g) \rightarrow 2Al_2O_3(s)[/tex]
Since aluminum and oxygen are in a 4:3 molar ratio, we compute the moles of oxygen that completely react as shown below:
[tex]n_{O_2}=719.68molAl*\frac{3molO_2}{4molAl} \\\\n_{O_2}=959.57molO_2[/tex]
Best regards.
