Answer :
Answer:
THE NEW VOLUME WHEN THE BALLOON TAKES OFF FROM THE MOUNTAINTOP IS 114.1 L
Explanation:
The question follows Boyle's law of gas laws and it involves pressure and volume being inversely proportional to the volume. As pressure increases, the volume decreases and vice versa.
Mathematically represented as:
P1V1 = P2 V2
P1 = 101.3 kPa = 101.3 * 10^3 Pa
V1 = 69.5 L
P2 = 61.7 kPa = 61.7 * 10^3 Pa
V2 = ?
making V2 the subject of the formula. we have;
V2 = P1 V1 / P2
V2 = 101.3 *10^3 * 69.5 / 61.7 *10^3
V2 = 7040.35 / 61.7
V2 = 114.106 L
The volume at a decreased pressure of 61.7 kPa at the mountaintop is 114.1 L
This is in line with Boyle's law which shows that at high pressure, volume decreases and at low pressure, volume increases.
Answer:
The new volume is 114.1 L
Explanation:
Step 1: Data given
Volume of the helium balloon = 69.5 L
The atmosphere pressure is 101.3 kPa
The pressure decreases to 61.7 kPa
Step 2: Calculate the new volume
P1*V1 = P2*V2
⇒with P1 = the atmosphere pressure is 101.3 kPa
⇒with V1 = the initial volume = of the helium balloon = 69.5 L
⇒with P2 = the decreased pressure = 61.7 kPa
⇒with V2 = the new volume = TO BE DETERMINED
101.3 kPa * 69.5 L = 61.7 kPa * V2
V2 = (101.3 kPA * 69.5 L ) / 61.7 kPa
V2 = 114.1 L
The new volume is 114.1 L