Answer :
Hello,
If you mean [tex]f(x)=log_2(3x+2)= \dfrac{ln(3x+2)}{ln(2)} \\ f'(x)= \dfrac{3}{ln(2)*(3x+2)} [/tex]
If you mean [tex]f(x)=log_2(3x+2)= \dfrac{ln(3x+2)}{ln(2)} \\ f'(x)= \dfrac{3}{ln(2)*(3x+2)} [/tex]