Answer :
Answer:
cos(315°) = [tex]\frac{\sqrt{2} }{2}[/tex]
sin(315°) = [tex]-\frac{\sqrt{2} }{2}[/tex]
Step-by-step explanation:
Khan Academy: Trig values of special angles (Alg II)
Answer:
cos(315°) = [tex]\frac{\sqrt{2} }{2}[/tex]
sin(315°) = [tex]-\frac{\sqrt{2} }{2}[/tex]
Step-by-step explanation:
Khan Academy: Trig values of special angles (Alg II)