Answer :
Answer:
Coordinates of M = [tex]\left ( -2,4 \right )[/tex]
Step-by-step explanation:
Given: AM:MB = 1:4, A has coordinates (-4, 3) and B has coordinates (6, 8)
To find: coordinates of M
Solution:
According to section formula, if M(x, y) divides line joining points [tex]A(x_1,y_1)\,,\,B(x_2,y_2)[/tex] in ratio [tex]m:n[/tex] then coordinates of point M are [tex]\left ( \frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n} \right )[/tex]
Put [tex]A(x_1,y_1)=(-4,3)\,,\,B(x_2,y_2)=(6,8)\,,\,m:n=1:4[/tex]
Therefore,
[tex](x,y)=\left ( \frac{6-16}{1+4},\frac{8+12}{1+4} \right )=\left ( -2,4 \right )[/tex]