We have that
The Matrix A is a singular square matrix and because its determinate is zero. No the Matrix A is inveritible because its determinant is not equal to zero.
Option E is correct
From the question we are Given the matrix:
[tex]A= \begin{bmatrix}6 & -4 \\-9 & 6\end{bmatrix}[/tex]
Invertible Matrix
In linear algebra, an n-by-n square matrix A is called invertible if there exists an n-by-n square matrix B such that
[tex]AB=BA=I_n[/tex]
where In denotes the n-by-n identity matrix and the multiplication used is ordinary matrix multiplication.
Invertible Matrix characteristics does not apply to singular square matrix, A square matrix is singular if and only if its determinant is zero
Generally the determinate of Matrix A is given as
[tex]A= \begin{bmatrix}6 & -4 \\-9 & 6\end{bmatrix}[/tex]
[tex]D=(6*6)-(-4*-9)\\\\D=0[/tex]
In conclusion
The Matrix A is a singular square matrix and because its determinate is zero.
So, No the Matrix A is inveritible because its determinant is not equal to zero.
Option E is correct
For more information on this visit
https://brainly.com/question/18028537
