Answer :
4 times the diference of f squared and g: 4(f²-g)
The sum of f squared an 2g : f²+2g
therefore, we have:
4(f²-g)+(f²+2g)=4f²-4g+f²+2g=5f²-2g
answer: 5f²-2g
The sum of f squared an 2g : f²+2g
therefore, we have:
4(f²-g)+(f²+2g)=4f²-4g+f²+2g=5f²-2g
answer: 5f²-2g