A professor gives his students the choice of 7 assignments. Each student has to complete 4 of the 7 assignments.

How many combinations of the 4 assignments are possible?

Answer :

Answer:

35 combinations

Step-by-step explanation:

[tex]\frac{7!}{4! * 3!} = \frac{7*6*5*4!}{4! * 3*2*1} = 35[/tex]

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