Answer :
Answer:
Step-by-step explanation:
The given function is
[tex]f(x)=(x-1)(x+7)[/tex]
Zeroes of the function are
[tex](x-1)(x+7)=0[/tex]
[tex]x=-7,1[/tex]
It means, f(x) intersect x-axis at x=-7 and x=1.
Mid value of -7 and 1 is the x-coordinate of the vertex.
[tex]\dfrac{-7+1}{2}=-3[/tex]
At x=-3,
[tex]f(-3)=(-3-1)(-3+7)=(-4)(4)=-16[/tex]
So, the vertex of the function is at (-3,-16).
The given function can be written as
[tex]f(x)=x^2+7x-x-7[/tex]
[tex]f(x)=x^2+6x-7[/tex]
Here leading coefficient is negative, it means it is an upward parabola.
So, we conclude that
1. The graph is increasing on the interval x > -3.
2. The graph is decreasing on the interval x < -3.
3. The graph is positive only on the intervals where x <-7 and where x > 1.
4. The graph is negative only on the intervals where -7 < x < 1.
Therefore, the correct options are 2, 3 and 4.
Answer:
THE CORRECT ANSWERS ARE 2,3,4!
Step-by-step explanation:
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