Answer:
B. The endpoint of the dilated line is (-2,4),(6,8)
Step-by-step explanation:
Given
Line segment AB
Endpoints: A(-3,6) and B(9,12)
Scale Factor: 2/3 about the origin
Required
Find the end points of the dilated line
From the question, we understand that the line segment is dilated about the origin;
The keywords about the origin implies that, to get the endpoints of the dilated line, we simply multiply the coordinates of of the original line by the scale factor;
This is shown below;
[tex]For\ A = (-3,6);[/tex]
The new endpoints become
[tex]A' = \frac{2}{3} A[/tex]
[tex]A' = \frac{2}{3} (-3,6)[/tex]
[tex]A' = (\frac{2}{3} * -3, \frac{2}{3} * 6)[/tex]
[tex]A' = (\frac{2* -3}{3}, \frac{2 * 6}{3})[/tex]
[tex]A' = (\frac{-6}{3}, \frac{12}{3})[/tex]
[tex]A' = (-2, 4)[/tex]
[tex]For\ B = (9, 12);[/tex]
The new endpoints become
[tex]B' = \frac{2}{3} B[/tex]
[tex]B' = \frac{2}{3} (9, 12)[/tex]
[tex]B' = (\frac{2}{3} * 9, \frac{2}{3} * 12)[/tex]
[tex]B' = (\frac{2* 9}{3}, \frac{2 * 12}{3})[/tex]
[tex]B' = (\frac{18}{3}, \frac{24}{3})[/tex]
[tex]B' = (6, 8)[/tex]
Hence, the endpoint of the dilated line is (-2,4),(6,8)
