Answered

Suppose that in a lightning flash the potential difference between a cloud and the ground is 1.0×109 V and the quantity of charge transferred is 31 C. (a) What is the change in energy of that transferred charge? (b) If all the energy released could be used to accelerate a 1100 kg car from rest, what would be its final speed?

Answer :

Answer:

(a )    [tex]3*10^{10} \ joules[/tex]

(b)   7507.57 m/s

Explanation:

Given information :

Potential difference=[tex]1.0\ *\ 10^{9} V[/tex]

Charge transferred = 31 C.

Mass to accelerated the car= 1100 kg

(a) The change in energy is determined by the following formula

[tex]E = Q *\ V[/tex]

where E= change in Energy

Q=Potential difference

V= Charge transferred

Putting the value of Potential difference and charge transferred in the given equation we get

[tex]E= 1.0*10^{9} \ * \ 31\\E=31*10^{9} \ Joules[/tex]

[tex]E=3.1 * 10^{10} \ Joules[/tex]

(b) Kinetic energy can be determined by the given formula

[tex]K= 0.5*m* v^{2} \\[/tex]

Putting the value of m and k in the previous equation

[tex]3.1 \ * 10^{10}= 0.5 * 1100 \ *\ v^{2}\\ 3.1 *10^{10} =550 \ *\ v^{2}\\\\v^{2}=\ \frac{ 3.1 *10^{10}}{550}[/tex]

v=7507.57 m/s

Other Questions