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Two parallel lines are crossed by a transversal. Parallel lines x and y are cut by transversal w. On line x where it intersects with line w, 4 angles are created. Labeled clockwise, from uppercase left, the angles are: 2, 4, 3, 1. On line y where it intersects with line w, 4 angles are created. Labeled clockwise, from uppercase left, the angles are: 6, 8, 7, 5. If mAngle6 = 123.5°, then mAngle1 is 56.5°. 67.5°. 123.5°. 136.5°.

Answer :

Answer:

(A)[tex]56.5^\circ[/tex]

Step-by-step explanation:

From the diagram attached:

Angle 1 and Angle 6 are Co-Interior Angles.

The sum of co-interior angle is 180 degrees.

Therefore:

[tex]m\angle 1+ m\angle 6=180^\circ\\\\m\angle 6=123.5^\circ,$ therefore:\\m\angle 1+ 123.5^\circ=180^\circ\\m\angle 1=180^\circ-123.5^\circ\\m\angle 1=56.5^\circ[/tex]

The measure of angle 1 is therefore 56.5 degrees.

The correct option is A.

${teks-lihat-gambar} Newton9022
akposevictor

∠6 and ∠1 are same-side interior angles, m∠6 = 123.5°, therefore m∠1 will be: A. 56.5°

Recall:

  • Same-side interior angles are supplementary to each other. They add up to give 180°.

The image showing the two parallel lines that is cut by a transversal creating angles is shown in the diagram attached below.

Given:

m∠6 = 123.5°

∠6 and ∠1 are same-side interior angles.

  • Therefore:

m∠6 + m∠1 = 180°

  • Substitute

123.5° + m∠1 = 180°

  • Subtract both sides by 123.5°

m∠1 = 180° - 123.5°

m∠1 = 56.5° (Option A)

Learn more about same-side interior angles on:

https://brainly.com/question/16873218

${teks-lihat-gambar} akposevictor

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