Answer :
Answer:
180,000 nucleotide pairs = 180 kilobase pair (kbp) = 0.18 Megabase pairs (Mbp)
Explanation:
Synthesis rate = 1,000 nucleotides (nts) x second
1 minute = 60 seconds
30 minutes = 60 x 30 = 1,800 seconds
>> 1,800 seconds x 1,000 nuleotides per second = 180,000 nts
A typical bacterial genome contains approximately 5 Mbps of DNA that conforms a circular chromosome localized in the cytoplasm. In consequence, in this case the bacterial genome is small (0.18 Mbp).
DNA replication is a process in which the fragment gets replicated to form two indistinguishable replicas of itself. It is vital for the growth and passing of hereditary information to the newly produced daughter cells.
180,000 nucleotide pairs are formed in the replicating bacteria.
This can be calculated by:
[tex]\text{Synthesis rate} & = 1,000 \;\text{nucleotides (nts)} \times \text{ second}[/tex]
- We know that 1 minute = 60 seconds
- So, 30 minutes = 60 x 30 = 1,800 seconds
[tex]\text{1,800 seconds} \times \text{ 1,000 nucleotide per second} & = 180,000 \;\text{nts}[/tex]
The bacterial genome thus produced will have 180,000 nucleotide pairs or 180 kilo-base pairs (kbp) or 0.18 Megabase pairs (Mbp) in the chromosome.
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