Answer:
0.086J/g°C
Explanation:
The following data were obtained from the question:
Mass (M) = 30g
Initial temperature (T1) = 10°C
Final temperature (T2) = 45°C
Change in temperature (ΔT) = T2 – T1 = 45°C – 10°C = 35°C
Heat (Q) released = 90J
Specific heat capacity (C) of wood =..?
We can obtain the specific heat capacity of the wood as follow:
Q = MCΔT
90 = 30 x C x 35
Divide both side by 30 x 35
C = 90/(30 x 35)
C = 0.086J/g°C.
Therefore, the specific heat capacity of the wood is 0.086J/g°C.
