Answer:
28.8 degrees bearing above from the east.
Step-by-step explanation:
Given :
Direction =30 degrees
Speed =724 km/hr
Suppose x1, y1 be the velocity bearing in the east at the 30 degree
so x1 velocity = 724 cos 30 degree
y1 velocity = 724 sin 30 degree
As mention in the question the wind speed adding another 32 to the x1 speed.
Hence the resultant speed is
[tex]velx1= 659\\vely1 = 362[/tex]
[tex]The \ speed\ is\ determined \ by \ following\ formula\ \\ \sqrt{vel y1^2+ velx1^2} \\= \sqrt{659^2+362^2}\\=751.9 km/hr\\therefore\ \ the\ direction is\ arctan \\= vely1/ velx1 \\= arctan( 362/659) \ =28.8\ degrees\ above\ from\ the\ east[/tex]
