Answer :
Answer:
[tex]\frac{5}{5+2}(3-1)+ 1[/tex]
Step-by-step explanation:
To find the coordinate of the point that divides a line segment AB with point A at ([tex]x_1,y_1[/tex]) and point B at [tex](x_2,y_2)[/tex] in the proportion c:d, the formula used to find the location of the point is:
[tex]x-coordinate:\\\frac{c}{c+d}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{c}{c+d}(y_2-y_1)+y_1[/tex]
Therefore the y coordinate that divides line segment CD with point C at ([tex]-4,1[/tex]) and point D at [tex](3,3)[/tex] in the proportion 5:2 is given by:
[tex]for\ y-coordinate:\\\frac{c}{c+d}(y_2-y_1)+y_1\\=\frac{5}{5+2}(3-1)+ 1\\=\frac{5}{7}(2)+1=\frac{17}{7}[/tex]