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The resistance RRR of a copper "gauge 10" jumper cable with diameter d=0.259d=0.259 cmcm is 0.0124 ΩΩ. Find the length LLL of the cable. Express your answer in mm. Use three significant figures.

Answer :

Answer:

The length will be "3.89 m".

Explanation:

The given values are:

Diameter,

d = 0.259 cm

On converting it in m, we get

d = 0.259 × 10⁻²            

Resistance

R = 0.0124 Ω      

As we know,

⇒  [tex]A=\pi (\frac{d}{2})^2[/tex]

On putting the estimated values, we get

        [tex]=3.14(\frac{0.259\times 10^{-2}}{2})^2[/tex]

        [tex]=5.266\times 10^{-6} \ m^2[/tex]

If, [tex]\rho = 1.68\times 10^{-8} \ \Omega.m[/tex]

then, [tex]R=\frac{\rho L}{A}[/tex]

         [tex]L=\frac{RA}{\rho}[/tex]

On substituting the values, we get

            [tex]=\frac{(0.0124)(5.266\times 10^{-6})}{1.68\times 10^{-8}}[/tex]

            [tex]=3.89 \ m[/tex]

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