Answer :
Answer:
The probability that a child is born with this genetic trait is 0.03.
Step-by-step explanation:
The probability that a woman is a carrier of a particular genetic trait is,
P (W) = 0.15.
The probability that a man is a carrier of a particular genetic trait is,
P (M) = 0.20.
The two events are independent of each other, since the event of a woman being a carrier is not affected by the man being a carrier and vice-versa.
It is provided that this trait can only be inherited by a child if both parents are carriers.
Compute the probability that both parents are carriers of the trait as follows:
[tex]P(W\cap M)=P(W)\times P(M)[/tex]
[tex]=0.15\times 0.20\\=0.03[/tex]
Thus, the probability that a child is born with this genetic trait is 0.03.