As a certain engine's rotation speed increases, its temperature increases at a constant rate. The table compares the engine's rotation speed (in cycles per second) and its temperature (in degrees Celsius).

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Answer:
15° Celsius.
Step-by-step explanation:
Begin by deriving an equation to represent the values in the table. Use the slope formula:
[tex]m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Plug in values from the table into the formula:
[tex]m = \frac{27.0 - 22.2}{15-9}[/tex]
Simplify:
[tex]m = \frac{4.8}{6}[/tex]
Reduces to:
m = 0.8. This is the slope of the equation.
Use a point from the table and plug it into the equation y = mx + b, along with the slope to calculate the y-intercept:
27 = 0.8(15) + b
27 = 12 + b
27 - 12 = b
b = 15. This represents the value when x = 0, therefore:
The engine's temperature at rest is 15° Celsius.