Answer :
Answer : The number of moles of solute [tex]Ca(OH)_2[/tex] is, 0.0788 moles.
Explanation : Given,
Molarity = 0.225 M
Volume of solution = 0.350 L
Formula used:
[tex]\text{Molarity}=\frac{\text{Moles of }Ca(OH)_2}{\text{Volume of solution (in L)}}[/tex]
Now put all the given values in this formula, we get:
[tex]0.225M=\frac{\text{Moles of }Ca(OH)_2}{0.350L}[/tex]
[tex]\text{Moles of }Ca(OH)_2=0.0788mol[/tex]
Therefore, the number of moles of solute [tex]Ca(OH)_2[/tex] is, 0.0788 moles.
Answer:
(0.225 M CaOH2) x (0.350 L) = 0.0788 mol CaOH2
Explanation:
edge 2021
For the second question: How many grams of CaOH2 are in this solution?
The molar mass of CaOH2 is 58.093 g/mol.
Answer:
(0.0787 mol CaOH2) x (58.093 g/mol) = 4.57g CaOH2
Explanation:
edge 2021