poopyeet
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Aram's four children are now 1, 5, 7, and 9 years old. In how many years will the sum of the ages of two of his children be twice the sum of the ages of the other two children?

Answer :

olivia3314

Answer:

In 2 years

Step-by-step explanation:

age right now 1,5,7,9

Let the number of years in which the sum of the ages of two of his children be twice the sum of the ages of the other two children=x

Therefore Age of the children after x years will be 1+x,5+x,7+x and 9+x

2[1+x + 5+x] = (7+x)+(9+x)

2[6+2x]= 7+9+x+x

12+4x=16+2x

4x-2x=16-12

2x=4

x=4/2=2

Let's verify if the answer is correct

-- Verify by substituting the value of x in this 2[1+x + 5+x] = (7+x)+(9+x)

2[1+2 + 5+2] = (7+2)+(9+2)

2[10]=9+11

20=20

Therefore 2 years is the answer

adioabiola

We are required to find the number of years when the ages of two of his children be twice the sum of the ages of the other two children?

The number of years it will take for two of his children be twice the sum of the ages of the other two children is 2 years

Child 1 = 1 year

Child 2 = 5 years

Child 3 = 7 years

Child 4 = 9 years

let

x = number of years it will take for two of his children be twice the sum of the ages of the other two children

twice the age of the two younger children in the unknown year equal the age of the two older children in the unknown year

2{(1 + x) + (5 + x)} = (7 + x) + (9 + x)

2(1 + x + 5 + x) = 7 + x + 9 + x

2(6 + 2x) = 16 + 2x

12 + 4x = 16 + 2x

12 - 16 = 2x - 4x

-4 = - 2x

divide both sides by -2

-4 / -2 = x

x = 2

Therefore,

The number of years it will take for two of his children be twice the sum of the ages of the other two children is 2 years

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