Answer: Choice C
angle HDG = angle HFE
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Explanation:
We have the statement [tex]\triangle DHG \cong \triangle FHE[/tex] given to us. Note that "H" is in the middle for both sequences of three letters. For DHG, start at H and move back one space to get to D. Move back another unit to wrap around to G. So the new sequence is HDG which forms the first angle.
Follow the same pattern but for FHE now. Start at H, move backward one spot to F, then move back again to wrap around to E. We have HFE
This shows angle HDG pairs up with angle HFE. The corresponding angles are congruent due to CPCTC
CPCTC = corresponding parts of congruent triangles are congruent
Notice how angles HDG and HFE are alternate interior angles, which lead to showing DG is parallel to EF.
