Answered

A circular loop of wire of radius 10 cm carries a current of 6.0 A. What is the magnitude of the magnetic field at the center of the loop

Answer :

Answer:

3.77x10^-5T

Explanation:

Magnetic field at center of the loop is given as

B=uo*I/2r =(4pi*10-7)*6/2*0.1

B=3.77*10-5Tor 37.7 uTi

Other Questions