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Determine if the vector u is in the column space of matrix A and whether it is in the null space of A.
u = -4 A = 1 0 3
-5 -2 -1 -4
3 3 -3 0
1 -1 3 6
A) In Col A, not in Nul A
B) Not in Col A, not in Nul A
C) In Col A and in NulA
D) Not in Col in Nul A

Answer :

Answer: d) Not in Col in Nul A

Step-by-step explanation: The definition of Column Space of an m x n matrix A is the set of all possible combinations of the columns of A. It is denoted by col A. To determine if a vector is a column space, solve the matrix equation:

A.x = b or, in this case, [tex]A.x=u[/tex].

To solve, first write the augmented matrix of the system:

[tex]\left[\begin{array}{cccc}1&0&3&-4\\-2&-1&-4&-5\\3&-3&0&3\\-1&3&6&1\end{array}\right][/tex]

Now, find the row-echelon form of matrix A:

1) Multiply 1st row by 2 and add 2nd row;

2) Multiply 1st row by -3 and add 3rd row;

3) MUltiply 1st row by 1 and add 4th row;

4) MUltiply 2nd row by -1;

5) Multiply 2nd row by 3 and add 3rd row;

6) Multiply 2nd row by -3 and add 4th row;

7) Divide 3rd row by -15;

8) Multiply 3rd row by -15 and add 4th row;

The echelon form matrix will be:

[tex]\left[\begin{array}{cccc}1&0&3&-4\\0&1&-2&13\\0&0&1&-\frac{51}{15}\\0&0&0&-13 \end{array}\right][/tex]

Which gives a system with impossible solutions.

But if [tex]A.x=0[/tex], there would be a solution.

Null Space of an m x n matrix is a set of all solutions to [tex]A.x=0[/tex], so vector u is a null space of A, denoted by null (A)

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