Answer :
Answer:
The value of M₁₁ is -6.
Step-by-step explanation:
The minor, [tex]M_{ij}[/tex] is the determinant of a square matrix, say P, formed by removing the ith row and jth column from the original square matrix, P.
The matrix provided is as follows:
[tex]A=\left[\begin{array}{ccc}7&9&-3\\3&-6&5\\4&0&1\end{array}\right][/tex]
The matrix M₁₁ is:
Remove the 1st row and 1st column to form M₁₁,
[tex]M_{11}=\left|\begin{array}{cc}-6&5\\4&0\end{array}\right|[/tex]
Compute the value of M₁₁ as follows:
[tex]M_{11}=\left|\begin{array}{cc}-6&5\\4&0\end{array}\right|[/tex]
[tex]=(-6\times 1)-(5\times 0)\\\\=-6-0\\=-6[/tex]
Thus, the value of M₁₁ is -6.