What is the area of a regular hexagon with an apothem 16.5 inches long and a side 19 inches long? Round the answer to the nearest tenth. A. 625.3 in.2 B. 940.5 in.2 C. 156.3 in.2 D. 1,875.8 in.2

Answer :

Answer: B. 940.5 square inches

==============================================

Explanation:

Any regular hexagon is really the combination of six identical (aka congruent) equilateral triangles glued together. If we can find the area of one triangle, then we multiply by 6 to get our final answer.

The apothem is the height of the equilateral triangle with the triangular base being the side length of the hexagon.

area of triangle = (1/2)*base*height

area of triangle = 0.5*(hexagon side length)*(apothem)

area of triangle = 0.5*19*16.5

area of triangle = 156.75

This is the area of one equilateral triangle. Having 6 triangles leads to a total area of 6*156.75 = 940.5 square inches

The area of a regular hexagon with an apothem of 16.5 inches and a side of 19 inches is Area of hexagon = 1/2(length of apothem)(perimeter of the hexagon) = 940.5 inches. (Option-B)

Apothem:

Apothem is a perpendicular line from the center of the regular polygon to one of its sides.

Area of Regular polygon with apothem:

Area = 1/2 x (length of apothem) x (perimeter of hexagon)

   • Given,  

     apothem = 16.5 inches and length of a side =19 inches

   • Perimeter = 6 x (side of a hexagon)

                       = 6 x (19)

                       = 114 inches

   • Hence,

      Area = 1/2 x (16.5) x (114) = 940.5 inches(rounded to the nearest tenth)

Know more about Regular hexagon :

https://brainly.com/question/10209400?referrer=searchResults

#SPJ2

Other Questions