Answer :

Answer:

t= 0

Step-by-step explanation:

Using the rules of logarithms

log x + log y = log(xy)

[tex]log_{b}[/tex] 1 = 0

Given

[tex]log_{x}[/tex] a + [tex]log_{x}[/tex] [tex]\frac{1}{a}[/tex] = t ,then

[tex]log_{x}[/tex] (a × [tex]\frac{1}{a}[/tex] ) = t

[tex]log_{x}[/tex] 1 = t , thus

t = 0

I’m pretty sure the answer is t=0

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