Answer :
Answer:
If the frequency of the source is increased the current in the circuit will decrease.
Explanation:
The current through the circuit is given as;
[tex]I = \frac{V}{Z}[/tex]
Where;
V is the voltage in the AC circuit
Z is the impedance
[tex]Z = \sqrt{R^2 + X_L^2}[/tex]
Where;
R is the resistance
[tex]X_L[/tex] is the inductive reactance
[tex]X_L[/tex] = ωL = 2πfL
where;
L is the inductance
f is the frequency of the source
Finally, the current in the circuit is given as;
[tex]I = \frac{V}{\sqrt{R^2 + (2\pi fL)^2} }[/tex]
From the equation above, an increase in frequency (f) will cause a decrease in current (I).
Therefore, If the frequency of the source is increased the current in the circuit will decrease.