(20 PTS) Someone explain to me why this is the case

Answer:
i is an imaginary number because i = [tex]\sqrt{-1}[/tex] and you can never take a square root of a negative number. Because i is equal to [tex]\sqrt{-1}[/tex] when you square it it just removes the square root sign and gives you -1
Step-by-step explanation:
Step-by-step explanation:
think of it as this: i is an imaginary number, so a negative in a square root will be negative. so if you take away the squareroot, it leave you with -1. a square root is ^2 so i^2 is practically the same as a square root.
If someone can explain better, please do