Answer :
Answer:
The minimum uncertainty in the velocity is 232.57 m/s.
Explanation:
Given that,
Location of a particle with uncertainty = 0.13 nm
Mass of particle [tex]m=1,745\times10^{-27}\ kg[/tex]
We need to calculate the minimum uncertainty in the velocity
Using heisenberg's uncertainty principle,
[tex]\Delta x\cdot \Delta p\geq \dfrac{h}{4\pi}[/tex]
[tex]\Delta x\cdot m\Delta v \geq \dfrac{h}{4\pi}[/tex]
[tex]\Delta v=\dfrac{h}{4\pi\times m\Delta x}[/tex]
Put the value into the formula
[tex]\Delta v=\dfrac{6.63\times10^{-34}}{4\pi\times 1.745\times10^{-27}\times0.13\times10^{-9}}[/tex]
[tex]\Delta v= 232.57\ m/s[/tex]
Hence, The minimum uncertainty in the velocity is 232.57 m/s.