Answer:
(a) The new angle the ladder makes with the ground = 32.66°
(b) The distance the ladder slipped back on the ground from it's original position = 5 m
Step-by-step explanation:
The given parameters are;
The length of the ladder = 10 m
Angle of inclination of the ladder = 70°
Length to which the ladder slips down the wall = 4 m
(a) The height of the wall adjacent to the ladder = 10×sin(70°) ≈ 9.4 m
The new height of the wall adjacent to the ladder after the ladder slips down 4 m = 9.4 - 4 = 5.4 m
Therefore, the new angle of inclination of the ladder = sin⁻¹(5.4/10) = 32.66°
The new angle the ladder makes with the ground = 32.66°
(b) The distance the ladder slipped back on the ground from its original position is found as follows
The initial distance of the base of the ladder from the wall = 10 × cos(70°) = 3.42 m
The distance of the base of the ladder from the wall after slipping 4 m down the wall = 10 × cos(32.66°) ≈ 8.42 m.
Therefore, the amount by which the ladder slip back on the ground from its original position = 8.42 - 3.42 = 5 m.
The distance the ladder slipped back on the ground from it's original position = 5 m.