PLZ HELP Find the value of x that makes ΔXYZ~PQR

Answer:
x = 8
Step-by-step explanation:
[tex] \triangle XYZ \sim\triangle PQR... (GIVEN) \\
\therefore \frac{XY}{PQ} = \frac{YZ}{QR}.. (csst) \\
\therefore \frac{20}{30}= \frac{x+6}{21}\\
\therefore \frac{2}{3}= \frac{x+6}{21}\\
\therefore \frac{2\times 21}{3}= {x+6}\\
\therefore 14= {x+6}\\
\therefore 14-6= {x}\\
\therefore 8= {x}\\
\huge \orange{\boxed {\therefore x = 8}} [/tex]