a body of mass 2kg is released from rest on a smooth plane at an angle of 60 degree to the horizontal.calculate the acceleration of the body down the plane (g=10ms-2​

Answer :

Answer:

8.66m/s2

Explanation:

from newton second laws F=ma

the force down the plane is the component force along the plane which is mgsin₩ so there fore

a= gsin₩ = 10sin60= 8.66m/s2

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