Answer :
Answer:
slope = 0
Step-by-step explanation:
x = 8 is a vertical line parallel to the y- axis
A line perpendicular to it is a horizontal line parallel to the x- axis.
The x- axis has a slope of zero thus the line perpendicular to x = 8 is zero
The slope of a line is simply the ratio of a change in the vertical axis to the horizontal axis. The line perpendicular to [tex]x = 8[/tex] has a slope of 0
Given that
[tex]x = 8[/tex]
See attachment for the line of [tex]x = 8[/tex]
First, we determine the slope of [tex]x = 8[/tex]
The slope of a line (m) is calculated as:
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]x = 8[/tex] means that, the value of x is always 8; irrespective of the y-value.
So:
[tex]x_2 = x_1 = 8[/tex]
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex] becomes
[tex]m = \frac{y_2 - y_1}{8-8}[/tex]
[tex]m = \frac{y_2 - y_1}{0}[/tex]
Assume the slope of the line perpendicular to [tex]x = 8[/tex] is [tex]m_2[/tex].
[tex]m_2[/tex] is calculated as follows:
[tex]m_2 = -\frac{1}{m}[/tex]
Substitute [tex]m = \frac{y_2 - y_1}{0}[/tex]
[tex]m_2 = -\frac{1}{(y_2 - y_1)/0}[/tex]
This gives
[tex]m_2 = -\frac{1\times 0}{y_2 - y_1}[/tex]
[tex]m_2 = -\frac{0}{y_2 - y_1}[/tex]
[tex]m_2 = -0[/tex]
[tex]m_2 = 0[/tex]
The slope of the line perpendicular to [tex]x = 8[/tex] is 0.
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