Answer :
◈ LHS :
[tex]:\implies\tt\:sin60\degree[/tex]
[tex]:\implies\bf\:\dfrac{\sqrt{3}}{2}[/tex]
◈ RHS :
[tex]:\implies\tt\:\dfrac{2tan30\degree}{1+tan^230\degree}[/tex]
[tex]:\implies\tt\:\dfrac{2\times \dfrac{1}{\sqrt{3}}}{1+{\large(}\dfrac{1}{{\sqrt{3}}}{\large)}^2}[/tex]
[tex]:\implies\tt\:\dfrac{2}{\sqrt{3}}\times \dfrac{3}{3+1}[/tex]
[tex]:\implies\tt\:\dfrac{2}{\sqrt{3}}\times \dfrac{3}{4}[/tex]
[tex]:\implies\bf\:\dfrac{\sqrt{3}}{2}[/tex]
Hence Proved !!