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for f(x)=(x-3)/(x^(2)-4), the function is at x=2 continuous discontinuous with an infinite discontinuity discontinuous with a jump discontinuity discontinuous with a point discontinuity

for f(x)=(x-3)/(x^(2)-4), the function is at x=2 continuous discontinuous with an infinite discontinuity discontinuous with a jump discontinuity discontinuous w class=

Answer :

gloriagyamfuaa399

Answer:

ITS UNDEFINED

Step-by-step explanation:

2-3)/2^2 - 4

-1/(4-4)

-1/0

ITS UNDEFINED

09pqr4sT

Answer:

[tex]\Large \boxed{\mathrm{discontinuous \ with \ a \ point \ discontinuity}}[/tex]

[tex]\rule[225]{225}{2}[/tex]

Step-by-step explanation:

[tex]\displaystyle f(x)=\frac{x-3}{x^2-4}[/tex]

When x = 2.

We can see that the denominator is equal to 0 when the input value is 2.

[tex]2^2-4=4-4=0[/tex]

Obtaining a zero in the denominator indicates a point of discontinuity.

In the graph below, we can see that the function is discontinuous at x = 2.

[tex]\rule[225]{225}{2}[/tex]

${teks-lihat-gambar} 09pqr4sT

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