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In a household, a business is run for an average of 6 hours per day. the total power consumed by a computer and its printer is 215 watts. in addition, a 75-w light bulb runs during the same 6 hours. if their utility charges 11.75 cents per kwh, how much do the owners pay every 30-days?

Answer :

jepessoa

Answer:

$6.13

Explanation:

total electricity consumed per hour = 215 watts (computer + printer) + 75 watts (lights) = 290 watts per hour

total electricity consumed per month = 290 watts x 6 hours x 30 days = 52,200 watts = 52.2 kwh

monthly electric bill associated to the business = 52.2 kwh x $11.75 = $6.1335 ≈ $6.13

Tundexi

the amount that the owners will pay every 30-days is $6.13.

Here, we are to calculate the amount that the owners will pay for electricity every month.

  • The total electricity consumed per hour equals watt of Computer&Printer + Light watt

Total electricity consumed per hour = 215 watts + 75 watts

Total electricity consumed per hour = 290 watts per hour

  • Total electricity consumed per month = Total electricity consumed per hour * 6 hours * 30 days

Total electricity consumed per month = 290 watts x 6 hours x 30 days

Total electricity consumed = 52,200 watts

Total electricity consumed = 52.2 kwh

  • Monthly electric bill = Total electricity consumed *  Utility charges per kwh

Monthly electric bill = 52.2 kwh x $11.75

Monthly electric bill = $6.1335

Monthly electric bill = $6.13

Therefore, the amount that the owners will pay every 30-days is $6.13.

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