1)
3 , -10
2)
10x + y
3)
2x-3y
Ques 1)
We are given an algebraic expression as:
[tex]11x^2-12x-10[/tex]
The following expression has three terms:
[tex]11x^2,-12x\ and\ -10[/tex]
and the constant term is the term in which the variable is of exponent 0.
Hence, here we have the constant term as: [tex]-10[/tex]
Ques 2)
We are given a expression in terms of x and y by:
[tex]7x+3x+2y-y[/tex]
when on simplifying this expression we have:
[tex]=(7+3)x+(2-1)y\\\\=10x+y[/tex]
Ques 3)
The expression is given by:
[tex]\dfrac{1}{2}(4x-6y)[/tex]
On using the distributive property i.e.
[tex]a(b+c)=a\cdot b+a\cdot c[/tex]
we have:
[tex]\dfrac{1}{2}(4x-6y)=\dfrac{1}{2}\times 4x+\dfrac{1}{2}\times (-6y)\\\\i.e.\\\\\dfrac{1}{2}(4x-6y)=2x-3y[/tex]
