Answer :
Answer:
[tex] \boxed{\sf Time \ taken \ (t) = 8.8 \ s} [/tex]
Given:
Initial velocity (u) = 0 m/s
Final velocity (v) = 44 m/s
Acceleration (a) = 5 m/s²
To Find:
Time taken (t)
Explanation:
From equation of motion we have:
[tex] \boxed{ \bold{v = u + at}}[/tex]
By substituting value of u, v & a in the equation we get:
[tex] \sf \implies 44 = 0 + 5t \\ \\ \sf \implies 44 = 5t \\ \\ \sf \implies 5t = 44 \\ \\ \sf \implies t = \frac{44}{5} \\ \\ \sf \implies t = 8.8 \: s[/tex]