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2.763 pounds of liquid Z would fill up 5.93 cups. What is the density of liquid Zin g/mL? (1 pound -453.59 grams, 1 cup - 236.59 ml)
.466 g/mL
?
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5
2.15 g/mL
6
.558 g/mL
.473 g/mL
7
.893 g/mL

Answer :

dsdrajlin

Answer:

0.895 g/mL

Explanation:

Step 1: Given data

Mass of liquid Z (m): 2.763 lb

Volume of liquid Z (V): 5.93 cups

Step 2: Convert "m" to grams

We will use the relationship 1 lb = 453.59 g.

[tex]2.763 lb \times \frac{453.59 g}{1lb} = 1,253g[/tex]

Step 3: Convert "V" to milliliters

We will use the relationship 1 cup = 236.59 mL.

[tex]5.93cup \times \frac{236.59mL}{1cup} = 1.40 \times 10^{3} mL[/tex]

Step 4: Calculate the density of the liquid Z

The density (ρ) of the liquid Z is equal to its mass divided by its volume.

[tex]\rho = \frac{m}{V} = \frac{1,253g}{1.40 \times 10^{3}mL } = 0.895 g/mL[/tex]

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