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A car can decelerate at -3.15 m/s2 without skidding when coming to rest on a level road.
What would its deceleration be if the road is inclined at 9.7∘ and the car moves uphill? Assume the same static friction coefficient.

Answer :

Answer:

Deceleration = 5.7 m/s²

Explanation:

We are given;

Deceleration of the car; d = -3.15 m/s²

Angle of inclination; θ = 9.7°

Coefficient of friction will be calculated as; μ = d/g = 3.15/9.81 = 0.3211

Now,the acceleration would be gotten from the formula;

a = g (sin(θ) + μ cos(θ))

Plugging in the relevant values to give;

a = 9.81[sin 9.7 + (0.3211 × cos (9.7)]

sin 9.7 and cos 9.7 are in radians, thus we have;

a = 9.81(-0.2718 + (0.3211 × -0.9624))

a = -5.7 m/s²

Negative acceleration means a Deceleration of 5.7 m/s²

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