Answer :
1. (77+x)/2=84
2. Harold needs at least a 91
Work:
first, you multiply both sides by 2; 77+x=168
then you subtract 77 from both sides; x=91
then you plug it back in to check; (77+91)/2=84 ; 168/2=84 ; 84=84
2. Harold needs at least a 91
Work:
first, you multiply both sides by 2; 77+x=168
then you subtract 77 from both sides; x=91
then you plug it back in to check; (77+91)/2=84 ; 168/2=84 ; 84=84
Answer:
[tex]\frac{77+x}{2} \geq 84[/tex]
Harold needs to get more than 91 on his second test
Step-by-step explanation:
Harold wants to get average of Two test grades in math class is atleast 84.
He got 77 on the first test. and Let x be the score of second test.
Average of two test is [tex]\frac{77+x}{2}[/tex]
Average is atleast 84. The inequality becomes
[tex]\frac{77+x}{2} \geq 84[/tex]
Now solve the inequality for x
[tex]\frac{77+x}{2} \geq 84[/tex]
Multiply both sides by 2
[tex]77+x\geq 168[/tex]
Subtract 77 from both sides
[tex]x\geq 91[/tex]
Harold needs to get more than 91 on his second test