Answer :
Answer:
The value is [tex]E = 3.5619 *10^{5} V/m [/tex]
Explanation:
From the question we are told that
The height of the airplane is [tex]h = 2010 \ m[/tex]
The first charge concentration is [tex]Q = 46.9 \ C[/tex]
The height of the first charge concentration is [tex]h_1 = 4090 \ m[/tex]
The second charge concentration is [tex]Q_2 = −59.7 \ C[/tex]
The height of the second charge concentration is [tex]h_1 = 570 \ m[/tex]
The electric field due to the first charge concentration is
[tex]E_1 = \frac{k * |Q_1|}{(h_1 -h)^2}[/tex]
Here k is the Coulomb constant given in the question
[tex]E_1 = \frac{8.98755*10^9 * |46.9|}{(4090 - 2010)^2}[/tex]
[tex]E_1 = 9.7429 *10^{4} \ V/m[/tex]
The electric field due to the second charge concentration is
[tex]E_2 = \frac{k * |-59.7|}{(h -h_2)^2}[/tex]
[tex]E_2 = \frac{8.98755*10^9 * |-59.7|}{(2010 - 570)^2}[/tex]
[tex]E_2 = 2.5876 *10^{5} V/m[/tex]
Generally the superposition principle can be applied in this question as follows
[tex]E = E_1 + E_2[/tex]
=> [tex]E = 9.7429 *10^{4}+ 2.5876 *10^{5} [/tex]
=> [tex]E = 3.5619 *10^{5} V/m [/tex]