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Mercury has an average distance to the sun of 0.39 AU. In two or more complete sentences, explain how to calculate the orbital period of Mercury and then calculate it.

Answer :

Erudite1
Orbital period of mercury can be calculated using the third law of Kepler which states that period squared equals to distance cubed, that is, (T1/T2)^2 = (a1/a2)^3 Where T1 is the orbital period of mercury, T2 is the earth orbital period and is equal to 1 year, that is, 365.25 days. a1 is the mercury axis and is equal to 0.39AU while a2 is the earth axis and is equal to 1AU. T^2 = (0.39)^3 = 0.059319 Therefore, T1 = 88 days.
ajeigbeibraheem

The orbital period of mercury is 88 days.

What is the Orbital Period of Mercury?

The Orbital Period of Mercury can be estimated by using the Kepler's third law.

According to Kepler's third rule, the sub axis of the orbits (distance cubed) are precisely proportionate to the squares of the planets' orbital periods.

Mathematically:

[tex]\mathbf{(\dfrac{T_1}{T_2})^2 = (\dfrac{a_1}{a_2})^3}[/tex]

here:

  • T₁ = Mercury's Orbital period
  • T₂ = Earth's Orbital period

[tex]\mathbf{(\dfrac{T_1}{1})^2 = (\dfrac{0.39}{1})^3}[/tex]

Making T₁ the subject and solving for T₁;

T₁ = 88 days

Learn more about Orbital Period of mercury here:
https://brainly.com/question/1766066

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