mlpino
Answered

Calculate the mass of H2O produced by metabolism of 3.0 kg of fat, assuming the fat consists entirely of tristearin (C57H110O6), a typical animal fat, and assuming that during metabolism, tristearin reacts with O2 to form only CO2 and H2O.

Answer :

Edufirst
You have to start by balancing the equation

This is the equation balanced:

[tex]2 C_{57} H_{110} O_{6} +163 O_{2} -\ \textgreater \ 114CO_{2} +110 H_{2} O[/tex]

Relation 2 mols of triestarin: 110 mol of water

To pass 2 mols of triesetarin you have to multiply by the molar mass of the compound.

The molar mass of the triestarin is calculated as 57*atomic mass of C + 110 atomic mass of H + 6*atomic mass of oxygen = 57*12 + 110*1 + 6*16 = 890 g/mol

Then 2 mols = 2 * 890 g/mol = 1780 g

Now pass 110 mol of water to grams using the molar mass of water (18 g/mol)

110 mol * 18 g/mol = 1980 g of water

Now the relation in grams is 1780 g of tristearin / 1980 g of water = 3000 g of triestarin / x grams of water.

Solving for x, x = 3000 g of triestarin * 1980 g of water /1780 g of triestarin

x = 3337 g of water = 3.3 kg of water

Answer: 3.3 kg of water

Other Questions