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A special deck of cards has 5 green cards , and 3 yellow cards. The green cards are numbered 1, 2, 3, 4, and 5. The yellow cards are numbered 1, 2, and 3. The cards are well shuffled and you randomly draw one card. G = card drawn is green E = card drawn is even-numbered a. How many elements are there in the sample space? b. P(E) = (Round to 4 decimal places)

Answer :

Answer:

a. 8

b. 0.3750

Step-by-step explanation:

a. The computation of elements in the sample space is shown below:-

Total number of cards = 5 + 3

= 8

Now, we need to pick one card

So,

The number of elements in sample space = Number of ways of picking one card from 8 cars

= [tex]8_{C}_{1}[/tex] = 8

b. The computation of P(E) is shown below:-

[tex]P(E) = \frac{n(E)}{n(S)} \\\\ = \frac{3_C_1}{8_C_1} \\\\ = \frac{3}{8}[/tex]

after solving the above equation we will get

= 0.3750

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