Answer :
Answer:
(a). The specific volume at the final state is 0.25 m³/kg.
(b). The energy transfer by work is 50.4 kJ.
(c). The energy transfer by heat is -10.4 kJ.
Negative sign shows the direction of heat
Explanation:
Given that,
Weight of carbon monoxide = 4 kg
Volume of tank = 1 m³
Constant rate of 14W for 1 hour
The specific internal energy of the carbon monoxide increases by 10 kJ/kg.
(a). We need to calculate the specific volume at the final state
Using formula of specific volume
[tex]V'=\dfrac{V}{m}[/tex]
Put the value into the formula
[tex]V'=\dfrac{1}{4}[/tex]
[tex]V'=0.25\ m^3/kg[/tex]
(b). We need to calculate the energy transfer by work
Using formula of work
[tex]W=Pt[/tex]
Where, P = power
t = time
Put the value into the formula
[tex]W=14\times1\times3600[/tex]
[tex]W=50.4\ kJ[/tex]
(c). The energy transfer by heat transfer, and the direction of the heat transfer
We need to calculate the [tex]\Delta U[/tex]
Using formula of internal energy
[tex]\Delta U=m\Delta u[/tex]
Put the value into the formula
[tex]\Delta U=4\times10[/tex]
[tex]\Delta U=40\ kJ[/tex]
We need to calculate the energy transfer by heat
Using formula of energy transfer
[tex]Q=\Delta U-W[/tex]
Put the value into the formula
[tex]Q=40-50.4[/tex]
[tex]Q=-10.4\ kJ[/tex]
Negative sign shows the direction of heat that is removed from CO.
Hence, (a). The specific volume at the final state is 0.25 m³/kg.
(b). The energy transfer by work is 50.4 kJ.
(c). The energy transfer by heat is -10.4 kJ.
Negative sign shows the direction of heat.