Answer :
Complete combustion of Hydrocarbons with Oxygen will produce CO₂ and H₂O
Combustion of butane (C₄H₁₀) :
[tex]\tt 2C_4H_{10}+26O_2\rightarrow 8CO_2+10H_2O[/tex]
2.46 g water(H₂O) were produced
- mol of water
[tex]\tt \dfrac{2.46}{18}=0.137[/tex]
- mol of butane
[tex]\tt \dfrac{2}{10}\times 0.137=0.0274[/tex]
- mass of butane
MW : 58,12 g/mol
[tex]\tt mass=mol\times MW\\\\mass=0.0274\times 58.12\\\\mass=\boxed{\bold{1.592~g}}[/tex]