Answer :

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Solve the system by substitution.
-9x-10y=12
−3x+3=y


X=2
Y= -3

Answer:

[tex]x=2\\y=-3[/tex]

Step-by-step explanation:

We have:

[tex]-9x-10y=12\\-3x+3=y[/tex]

Since we already have a variable value ([tex]y[/tex]) in the second equation, it would be easiest to substitute the value for [tex]y[/tex] in the first equation:

[tex]-9x-10(-3x+3)=12[/tex]

Distribute [tex]-10[/tex] into [tex](-3x+3)[/tex]:

[tex]-9x+30x-30=12[/tex]

Combine like terms:

[tex]21x-30=12[/tex]

Add [tex]30[/tex] to both sides of the equation:

[tex]21x=42[/tex]

Divide by the coefficient of [tex]x[/tex], which is [tex]21[/tex]:

[tex]x=2[/tex]

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Now that we have our [tex]x[/tex] value, we can substitute that in to the second equation to find our [tex]y[/tex] value:

[tex]-3(2)+3=y[/tex]

Multiply:

[tex]-6+3=y[/tex]

Combine like terms:

[tex]-3=y[/tex]

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